(3y+5)(y^2-3y+4)=0

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Solution for (3y+5)(y^2-3y+4)=0 equation: 


Simplifying
(3y + 5)(y2 + -3y + 4) = 0

Reorder the terms:
(5 + 3y)(y2 + -3y + 4) = 0

Reorder the terms:
(5 + 3y)(4 + -3y + y2) = 0

Multiply (5 + 3y) * (4 + -3y + y2)
(5(4 + -3y + y2) + 3y * (4 + -3y + y2)) = 0
((4 * 5 + -3y * 5 + y2 * 5) + 3y * (4 + -3y + y2)) = 0
((20 + -15y + 5y2) + 3y * (4 + -3y + y2)) = 0
(20 + -15y + 5y2 + (4 * 3y + -3y * 3y + y2 * 3y)) = 0
(20 + -15y + 5y2 + (12y + -9y2 + 3y3)) = 0

Reorder the terms:
(20 + -15y + 12y + 5y2 + -9y2 + 3y3) = 0

Combine like terms: -15y + 12y = -3y
(20 + -3y + 5y2 + -9y2 + 3y3) = 0

Combine like terms: 5y2 + -9y2 = -4y2
(20 + -3y + -4y2 + 3y3) = 0

Solving
20 + -3y + -4y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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